Alternating emf: ε = ε₀ sin ωtप्रत्यावर्ती emf: ε = ε₀ sin ωtAlternating emf: ε = ε₀ sin ωt

NCERT Fig 6.14 · Class 12 Physics · Chapter 6 · interactive diagram

Parts and what they mean

• Induced emf ε = NBAω sin ωt (प्रेरित emf ε = NBAω sin ωt) — Goes between +ε₀ and −ε₀ every turn: its polarity keeps reversing, so the current is alternating.
• Flux per turn BA cos ωt (प्रति फेरा फ्लक्स BA cos ωt) — emf is largest where the flux changes fastest (crossing zero), and zero where flux is maximum.
• Peak emf ε₀ = NBAω (शिखर emf ε₀ = NBAω) — Reached at θ = 90° and 270° (coil plane parallel to B).
• Coil orientation (end view) (कुंडली की स्थिति (सिरे से दृश्य)) — At 0° the area vector is along B (coil face-on to the field); at 90° the coil plane is along B.

Original diagram drawn by Simple Learning Hub, based on NCERT Fig 6.14. Report a mistake