First order reaction: log([R]₀/[R]) vs timeप्रथम कोटि अभिक्रिया: log([R]₀/[R]) बनाम समयFirst order reaction: log([R]₀/[R]) vs time
NCERT Fig 3.5 · Class 12 Chemistry · Chapter 3 · interactive diagram
Parts and what they mean
- log([R]₀/[R]) vs t is a straight line (log([R]₀/[R]) बनाम t सरल रेखा) — From k = (2.303/t) log([R]₀/[R]).
- Slope = k/2.303 (ढलान = k/2.303) — So k = 2.303 × slope.
- Line passes through the origin (रेखा मूल बिंदु से गुज़रती है) — At t = 0, [R] = [R]₀ and log 1 = 0.
- log([R]₀/[R]) vs time (log([R]₀/[R]) बनाम समय) — log uses base 10; ln = 2.303 log.
Original diagram drawn by Simple Learning Hub, based on NCERT Fig 3.5. Report a mistake