Deriving the kinematic equationsशुद्धगतिक समीकरणों की व्युत्पत्ति

NCERT Fig 4.19 · interactive diagram

Parts and their functions

• Velocity-time axes (वेग-समय अक्ष) — Velocity at t = 0 is u; at time t it is v.
• Straight line, slope a (सीधी रेखा, ढलान a) — Constant acceleration: a = (v − u)/t ⇒ v = u + at.
• Rectangle = u × t (आयत = u × t) — Displacement if velocity had stayed u.
• Triangle = ½ t (v − u) = ½ at² (त्रिभुज = ½ t (v − u) = ½ at²) — Extra displacement due to acceleration. Total s = ut + ½at². Eliminating t gives v² = u² + 2as.

Original diagram drawn by Simple Learning Hub, based on NCERT Fig 4.19. Report a mistake