Temperature vs heat: ice → water → steamताप बनाम ऊष्मा: बर्फ़ → जल → भाप

NCERT Fig 10.10 · interactive diagram

Parts and their functions

• Ice warming (बर्फ़ गर्म होती) — Q = m s_ice ΔT (s_ice ≈ 2100 J kg⁻¹ K⁻¹).
• Melting at 0 °C (0 °C पर पिघलना) — Temperature constant while heat breaks the solid structure: Q = mL_f, L_f = 3.33 × 10⁵ J kg⁻¹.
• Water warming (जल गर्म होता) — Q = m s_w ΔT (s_w = 4186 J kg⁻¹ K⁻¹) — the steepest-heat part per degree.
• Boiling at 100 °C (100 °C पर उबलना) — Q = mL_v, L_v = 22.6 × 10⁵ J kg⁻¹ — much larger than L_f, so this flat part is longest.

Original diagram drawn by Simple Learning Hub, based on NCERT Fig 10.10. Report a mistake