Bob just completing a vertical circleऊर्ध्वाधर वृत्त पूरा करता गोलक
NCERT Fig 5.6 · interactive diagram
Parts and their functions
- Semicircular path A → B → C (अर्धवृत्ताकार पथ A → B → C) — Only gravity does work (tension is ⟂ to motion), so mechanical energy is conserved.
- String length L (डोरी की लंबाई L) — Radius of the circle.
- Lowest point A (निम्नतम बिंदु A) — E = ½mv₀² = (5/2)mgL ⇒ v₀ = √(5gL).
- Point B (level of O) (बिंदु B (O के तल पर)) — ½mv_B² + mgL = (5/2)mgL ⇒ v_B = √(3gL). K_B/K_C = 3.
- Top point C (शीर्ष बिंदु C) — Tension just zero: mg = mv_C²/L ⇒ v_C = √(gL); E = ½m(gL) + 2mgL = (5/2)mgL.
- Path after C (C के बाद पथ) — The string is slack, so the bob moves like a horizontally projected body — a parabola.
Original diagram drawn by Simple Learning Hub, based on NCERT Fig 5.6. Report a mistake